The power of a water jet flowing through an orifice of radius $r$ with velocity $v$ is

z e r o

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500 r^{2} v^{2}

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500 r^{3} v^{3}

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r^{4} v

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Solution

The correct option is C $500 r^{3} v^{3}$
Power = KE imparted to water in one second

$= \frac{1}{2} \frac{m v^{2}}{t}$

$= \frac{1}{2} \times$ mass flowing per second $\times v^{2}$

$= \frac{1}{2} \times A v ρ \times v^{2}$

$= \frac{1}{2} \times A v^{3} ρ$

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The power of a water jet flowing through an orifice of radius r with velocity v is

The correct option is C 500 r3v3Power = KE imparted to water in one second=12mv2t=12× mass flowing per second ×v2=12×Avρ×v2=12×Av3ρ

The power of a water jet flowing through an orifice of radius $r$ with velocity $v$ is

The correct option is C $500 r^{3} v^{3}$
Power = KE imparted to water in one second

$= \frac{1}{2} \frac{m v^{2}}{t}$

$= \frac{1}{2} \times$ mass flowing per second $\times v^{2}$

$= \frac{1}{2} \times A v ρ \times v^{2}$

$= \frac{1}{2} \times A v^{3} ρ$