The power of an electric pump is $20 W$ . How much volume of water per minute can the pump raise to a height of $10 m$ . Take acceleration due to gravity $g = 10 m s^{- 2}$ , density of water $ρ = 1000 k g m^{- 3}$ .

1.2 m^{3}

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0. 12 m^{3}

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0.012 m^{3}

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0.00 12 m^{3}

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Solution

The correct option is C $0.012 m^{3}$
Work done $= m g h$ where $m$ is the mass, $g$ is the acceleration due to gravity and $h$ is the height.
Given, time = $1 m i n u t e = 60 s e c o n d s$
height $h = 10 m$
$Power = \frac{Work done}{Time taken}$
$Power = \frac{mgh}{Time taken}$
So, $20$ = $\frac{m \times 10 \times 10}{60}$
$\Rightarrow m = 12 k g$
We know
$D e n s i t y = \frac{M a s s}{V o l u m e}$
$\Rightarrow V o l u m e = \frac{12}{1000}$
Therefore, the pump can raise water of volume $0.012 m^{3}$ in one minute.

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The power of an electric pump is 20 W. How much volume of water per minute can the pump raise to a height of 10 m. Take acceleration due to gravity g=10 ms−2, density of water ρ=1000 kgm−3.

The power of an electric pump is $20 W$ . How much volume of water per minute can the pump raise to a height of $10 m$ . Take acceleration due to gravity $g = 10 m s^{- 2}$ , density of water $ρ = 1000 k g m^{- 3}$ .