The power of halides of boron to act as Lewis acids decreases in the order:

$B F_{3}$ $>$ $B C l_{3}$ $>$ $B B r_{3}$

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$B B r_{3}$ $>$ $B C l_{3}$ $>$ $B F_{3}$

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$B C l_{3}$ $>$ $B F_{3}$ $>$ $B B r_{3}$

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$B C l_{3}$ $>$ $B B r_{3}$ $>$ $B F_{3}$

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Solution

The correct option is B
$B B r_{3}$ $>$ $B C l_{3}$ $>$ $B F_{3}$

Back bonding tendency decreases from F to I

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Similar questions

The correct order of Lewis acidity of $B X_{3}$ molecule is

B F_{3}, B C l_{3}

B B r_{3}

B F_{3}

B C l_{3}

B B r_{3}

B I_{3}

B B r_{3}, B C l_{3}

B F_{3}

B B r_{3}, B C l_{3} a n d B F_{3}

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