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Question

The power of P(1,2) with respect to the circle x2+y2+4x+2y+3 = 0 is double the power of P with respect to x2+y2+2x+y+k = 0 then the value of k is


A

1

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B

0

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C

-1

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D

4

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Solution

The correct option is C

-1


P(1,2)
x2+y2+4x+2y+3 = 0
S11 = 1+4+4+4+3
S11 = 8
For x2+y2+2x+y+k = 0
S11= 1+4+2+2+k = 9+k
2(9+k)=16
k = 89 = 1


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