wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The power of P(1,2) with respect to the circle x2+y2+4x+2y+3 = 0 is double the power of P with respect to x2+y2+2x+y+k = 0 then the value of k is


A

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

-1


P(1,2)
x2+y2+4x+2y+3 = 0
S11 = 1+4+4+4+3
S11 = 8
For x2+y2+2x+y+k = 0
S11= 1+4+2+2+k = 9+k
2(9+k)=16
k = 89 = 1


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Polarising Light
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon