The power (P) of an engine lifting a mass of $100 k g$ upto a height of $10 m$ in $1$ min is

P = 163.3 W

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P = 9800 W

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P = 10000 W

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P = 5000 W

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Solution

The correct option is A $P = 163.3 W$
To lift a mass, force applied should be just sufficient
$F = m g$
$∴ W o r k d o n e = F \times s$
$= (100 \times 9.8) \times 10$
$= 9800 J$
$∴ P o w e r = \frac{9800}{60} = 163.3 w a t t$

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The power (P) of an engine lifting a mass of 100kg upto a height of 10m in 1 min is

The correct option is A P=163.3WTo lift a mass, force applied should be just sufficientF=mg ∴Workdone=F×s =(100×9.8)×10 =9800J∴Power=980060=163.3watt

The power (P) of an engine lifting a mass of $100 k g$ upto a height of $10 m$ in $1$ min is

The correct option is A $P = 163.3 W$
To lift a mass, force applied should be just sufficient
$F = m g$
$∴ W o r k d o n e = F \times s$
$= (100 \times 9.8) \times 10$
$= 9800 J$
$∴ P o w e r = \frac{9800}{60} = 163.3 w a t t$