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2nd Equation of Motion

The power tha...

Question

The power that the engine must develop in order to take the vehicle of mass $2000 k g$ up an inclined plane of slope $1$ in $10$ at constant speed of $10 m s^{- 1}$ , if the frictional force is $200 N$ will be ( $g = 10 m s^{- 2}$ )

22 k W

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210 k W

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21000 k W

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2100 k W

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Solution

The correct option is A $22 k W$
Downward force $F = m g s i n θ + f r i c t i o n a l f o r c e$
$F = 2000 \times 10 \times \frac{1}{10} + 200$
$F = 2200 N$
$P = F V = 2200 \times 10 = 22000 W = 22 K W$

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