Question

The present age of a father is three years more than three times the age of the son. Three years hence, father's age will be $10$ years more than twice the age of the son. Determine their present ages.

Answer 1

Let the son's age be $x$

Then , according to the condition,

father's age $=3x+3$

$3$ years later:

Son's age $=x+3$

Father's age $=3x+3+3=3x+6$

According to the condition given ,

$3x+6=10+2(x+3)$

$3x+6=10+2x+6$

$x=10$

Thus , the son's present age is $10$ years and the father's age is

$3x+3=3\times 10+3=33$ years.