Question

The present age of A is twice that of B. After 30 years from now the age of A will be $1^{1/2}$ times that of B. Find the present ages of A and B respectively.

• A. $60,30$
• B. $30,60$
• C. $40,50$
• D. $50,40$

Answer 1

Answer: (A)

$60,30$

Present age :
A = 2x, B = x
After 30 years :
A = 2X + 30, B = X + 30
so,$2x+30=1^{1/2}(x+30)$
4x + 60 = 3x + 90
x = 30
$\therefore$ Present age of B = 30 years
Present age of A = 2 x 30 = 60 years