Question

The present age of A is twice to that of B. $30$ years from now, age of A will be $1\frac{1}{2}$ times that of B. The present ages of A and B(in years) respectively, are __________.

• A. $60,30$
• B. $30,60$
• C. $40,50$
• D. $50,40$

Answer 1

The correct option is B $30,60$

Let the present age of A be $x$ years and B be $2x$ years.

After $30$ years, age of Ais $\frac{3}{2}$ times of B

$\therefore$ $(x+30)\times \frac{3}{2}$= $(2x+30)$

$\therefore$ $3x+90=4x+60$

$\therefore$ $x=30$, $2x=60$