The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages.
Let present age of son = x year
Then age of his father = 2x
8 years hence,
Age of son = (x+8) years
and age of father = (2x + 8) years
According to the condition,
2x+8x+8=74
⇒ 8x + 32 = 7x + 56
⇒ 8x - 7x = 56 - 32 ⇒ x = 24
∴ Present age of son = 24 years
and age of father = 2x = 2 × 24 = 48 years
Hence age of man = 48 years and age of his son = 24 years