The present ages of a father and his son are in the ratio $7 : 3$ and the ratio of their ages will be $2 : 1$ after $10$ years. Then, the present age of father (in years) is

42

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56

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70

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77

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Solution

The correct option is C $70$
$L e t t h e p r e s e n t a g e s o f t h e f a t h e r & t h e s o n b e 7 x & 3 x r e s p e c t i v e l y . T h e n, a f t e r 10 y e a r s t h e s o n^{'} s a g e = 3 x + 10 & t h e f a t h e r^{'} s a g e = 7 x + 10. ∴ B y t h e g i v e n c o n d i t i o n \frac{7 x + 10}{3 x + 10} = \frac{2}{1} ⟹ 6 x + 20 = 7 x + 10 ⟹ x = 10. ∴ T h e f a t h e r^{'} s p r e s e n t a g e = 7 x = 7 \times 10 y r s . = 70 y r s . A n s - O p t i o n C .$

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Similar questions

Present age of father is 42 years and that of his son is 14 years. Find the ratio of

(a) Present age of father to the present age of son.

(b) Age of the father to the age of son, when son was 12 years old.

(d) Age of father to the age of son when father was 30 years old.

8 : 3

10

2 : 1

30

6

5 : 2 ?

Question 16(c)

The present age of the father is 42 years and that of his son is 14 years. Find the ratio of:

Age of father after 10 years to the age of son after 10 years.

25

8

13 : 8

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