Question

The present ages of three persons are in proportions 4: 7: 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)

• A. 8, 20, 28
• B. 16, 28, 36
• C. 20, 35, 45
• D. 10 , 18, 28
• E. None of these

Answer 1

The correct option is B

16, 28, 36

Let their present ages be 4x, 7 x and 9x years respectively.

Then, (4x - 8) + (7 x - 8) + (9x + 8) =56$\iff$20x = 80

x = 4

$\therefore$Their present ages are 16 years, 28 years and 36 years respectively