The present ages of three persons are in the ratio $4 : 7 : 9$ . Eight years ago the sum of their ages was $56$ . Find their present ages(in years).

16

years,

28

years,

36

years

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8

years,

14

years,

18

years

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12

years,

21

years,

29

years

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None of the above

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Solution

The correct option is B $16$ years, $28$ years, $36$ years
let the present ages be $4 x, 7 x, 9 x$
then the respective ages $8$ years ago will be,
$4 x - 8, 7 x - 8$ and $9 x - 8$
According to the question
$4 x - 8 + 7 x - 8 + 9 x - 8 = 56$
$20 x = 80$
$x = 4$
their present ages are,
$4 x = 4 \times 4 = 16 y e a r s$
$7 x = 7 \times 4 = 28 y e a r s$
$9 x = 9 \times 4 = 36 y e a r s$

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