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Question

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).


A

8, 20, 28

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B

16, 28, 36

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C

20, 35, 45

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D

none of these

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Solution

The correct option is B

16, 28, 36


Let their present ages be 4x, 7xand 9xyears respectively.

Then, (4x- 8) + (7x- 8) + (9x- 8) = 56

20x= 80

x= 4

therefore, Their present ages are 4x= 16 years, 7x= 28 years and 9x= 36 years respectively.


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