The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
16, 28, 36
Let their present ages be 4x, 7xand 9xyears respectively.
Then, (4x- 8) + (7x- 8) + (9x- 8) = 56
20x= 80
x= 4
therefore, Their present ages are 4x= 16 years, 7x= 28 years and 9x= 36 years respectively.