The present population of a town is $14000$ . If it increases at the rate of $10 %$ per annum, what will be its population after $4$ years?

10497

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20497

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30497

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40497

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Solution

The correct option is C $20497$
Population after $4$ years $=$ $Present Population$ ${(1 + \frac{r}{100})}^{n}$
Population after $4$ years $=$ $14000 \times {(1 + \frac{10}{100})}^{4}$
$= 14000 \times 1.4641$

$= 20497$
Population after $4$ years $= 20497$

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The present population of a town is 14000. If it increases at the rate of 10% per annum, what will be its population after 4 years?

The correct option is C 20497Population after 4 years = Present Population (1+r100)nPopulation after 4 years = 14000×(1+10100)4 =14000×1.4641 =20497Population after 4 years =20497

The present population of a town is $14000$ . If it increases at the rate of $10 %$ per annum, what will be its population after $4$ years?

The correct option is C $20497$
Population after $4$ years $=$ $Present Population$ ${(1 + \frac{r}{100})}^{n}$
Population after $4$ years $=$ $14000 \times {(1 + \frac{10}{100})}^{4}$
$= 14000 \times 1.4641$

$= 20497$
Population after $4$ years $= 20497$