Question

The present population of a town is $2,00,000$. Its population increases by $10$% in the first year and $15$% in the second year. Find the population of the town at the end of the two years.

Answer 1

Given : $P=2,00,000$
Population after first year

$=2,00,000{(1+\frac{10}{100})}^1$
$=2,00,000\left(\frac{110}{100}\right)=2,20,000$

Principal for the second year $=2,20,000$
Population at the end of second year

$=2,20,000{[1+\frac{15}{100}]}^1$
$=2,20,000\times \frac{115}{100}$
$=2,53,000$