The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.

Open in App

Solution

$Here, P = Initial population = 25, 000 R_{1} = 4 % R_{2} = 5 % R_{3} = 8 % n = Number of years = 3 ∴ Population after three years = P (1 + \frac{R_{1}}{100}) (1 + \frac{R_{2}}{100}) (1 + \frac{R_{3}}{100}) = 25, 000 (1 + \frac{4}{100}) (1 + \frac{5}{100}) (1 + \frac{8}{100}) = 25, 000 (1.04) (1.05) (1.08) = 29, 484 Hence, the population after three years will be 29, 484 .$

Suggest Corrections

Similar questions

The present population of a town is 25000. It grows at $4 %, 5 %$ and $8 %$ during first year, second year and third year respectively. Find its population after 3 years.

Q. Population of a town three years ago was

60, 000

. If the annual increase during three successive years be at the rate of

4 %, 5 %

and

6 %

respectively, find its present population.

Q. The population of a town 3 years ago was 25000.If the population in these three years has increased at the rate of 10%,15% and 8% respectively,find the present population.

Q. Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 5%, 4% and 3% respectively, what is its present population?

Q. Three years ago, the population of a town was 50000. If the annual increase during three successive years be at the rate of 4%, 5% and 3% respectively, find the present population.

Join BYJU'S Learning Program

The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.

Here,P=Initial population=25,000R1=4%R2=5%R3=8%n=Number of years=3∴ Population after three years=P1+R11001+R21001+R3100=25,0001+41001+51001+8100=25,0001.041.051.08=29,484Hence, the population after three years will be 29,484.