Question

The present population of a town is $25,000.$ It grows at $4\%,$ $5\%$ and $8\%$ during first year, second year and third year respectively, the population after $3$ years is

• A. $29,484$
• B. $28,696$
• C. $24,576$
• D. $30,184$

Answer 1

The correct option is A $29,484$

Let the rate of popukation be $p,q,r$ respectively.

Therefore, population after $3$ years is
$=p(1+\frac{p}{100})(1+\frac{q}{100})(1+\frac{r}{100})$
$=25000\times (1+\frac{4}{100})\times (1+\frac{5}{100})\times (1+\frac{8}{100})$
$=25000\times \frac{26}{25}\times \frac{21}{20}\times \frac{27}{25}=29,484$