wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The pressure acting on a submarine is 3×105 Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be: (Assume that atmospheric pressure is 1×105 Pa, density of water is 103 kg m3, acceleration due to gravity g=10 m s2)

A
2003%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
5200%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2005%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3200%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2003%
Pressure at depth h is
P=P0+hρg=3×105 Pa
hρg=3×1051×105
hρg=2×105 Pa

As h is doubled, 2hρg=4×105 Pa
Increased pressure, P=P0+2hρg
P=P0+4×105=5×105 Pa

% increase in pressure =PPP×100
=(53)×1053×105×100
=2003%

Hence, option (a) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Pressure at a Depth in a Liquid
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon