The pressure amplitude in a medium through which sound is travelling is 1.5×10−3N/m2 and intensity is 10−6W/m2. If the pressure amplitude is increased to 4.5×10−3N/m2 by increasing the volume of sound then the intensity will be
A
6×10−6W/m2
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B
7×10−6W/m2
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C
8×10−6W/m2
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D
9×10−6W/m2
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Solution
The correct option is D9×10−6W/m2 We know that the intensity of sound is given by, I=P2ov2B where, Po is the maximum pressure in the medium, v is the speed of sound and B is the bulk modulus of the medium. Medium of sound is same. So, I1I2=P2o1P2o2 ⇒I2=I1P2o2P2o1 ⇒I2=10−6×(4.5×10−3)2(1.5×10−3)2 ⇒I2=9×10−6W/m2