The pressure at depth h below the surface of a liquid of density - open to the atmosphere is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Pascal's Law

The pressure ...

Question

The pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is

Greater than the atmospheric pressure by

ρ g h

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Less than the atmospheric pressure by

ρ g h

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Equal to the atmospheric pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Decreases exponentially with depth

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Increases exponentially with depth

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Greater than the atmospheric pressure by $ρ g h$
Pressure at depth $h$ to the open surface
$p = p_{0} + h ρ g$ .
i.e., the pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is greater than the atmosphere pressure by $ρ g h$ .

Suggest Corrections

Similar questions

Q. Small air bubble of radius

r

is found to form at a depth of

H

from the open surface of the liquid contained in a beaker. If

S

is the surface tension,

ρ

is the density of the liquid and

P_{0}

is the atmospheric pressure, then the pressure inside the bubble is

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration

^{'} a^{'}

. The pressure in the liquid at a depth

h

below the free surface of the liquid is (consider atmospheric pressure to be

P_{0}

)

Q. In a cylindrical container, open to the atmosphere from the top, a liquid is filled upto 10 m depth. Density of the liquid varies with depth from the surface as

ρ (h) = 100 + 6 h^{2}

where

h

is in meter and

ρ

is in

k g / m^{3}

. The pressure at the bottom of the container will be: (atmospheric pressure =

10^{5} P a

g = 10 m / s e c^{2}

)

In the given figure the atmospheric pressure is equal to ρgh. Which of the following is not always correct when the simple barometer is accurately measuring the atmospheric pressure?

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration

^{'} a^{'}

. The pressure in the liquid at a depth

h

below the free surface of the liquid is (consider atmospheric pressure to be

P_{0}

)

Join BYJU'S Learning Program

The pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is

The correct option is A Greater than the atmospheric pressure by ρghPressure at depth h to the open surfacep=p0+hρg.i.e., the pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is greater than the atmosphere pressure by ρgh.

The pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is

The correct option is A Greater than the atmospheric pressure by $ρ g h$
Pressure at depth $h$ to the open surface
$p = p_{0} + h ρ g$ .
i.e., the pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is greater than the atmosphere pressure by $ρ g h$ .