The pressure at depth h below the surface of a liquid of density - open to the atmosphere is

In the given figure the atmospheric pressure is equal to ρgh. Which of the following is not always correct when the simple barometer is accurately measuring the atmospheric pressure?

Q. A beaker containing a liquid of density

ρ

moves up with an acceleration

^{'} a^{'}

. The pressure in the liquid at a depth

h

below the free surface of the liquid is (consider atmospheric pressure to be

P_{0}

)

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The pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is

The correct option is A Greater than the atmospheric pressure by ρghPressure at depth h to the open surfacep=p0+hρg.i.e., the pressure at depth h below the surface of a liquid of density ρ open to the atmosphere is greater than the atmosphere pressure by ρgh.

The pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is

The correct option is A Greater than the atmospheric pressure by $ρ g h$
Pressure at depth $h$ to the open surface
$p = p_{0} + h ρ g$ .
i.e., the pressure at depth $h$ below the surface of a liquid of density $ρ$ open to the atmosphere is greater than the atmosphere pressure by $ρ g h$ .