Question

The pressure difference across a pipe of $5cm$ is $2\times {10}^{3}pa.$ Work done by the pressure in forcing $2m^3$ of water through the pipe in $joule$ is:

Answer 1

Water moved (Area)$=2m^3$
Pressure$={10}^{5}Pa.$

Radius of the pipe(Length)$=1cm.$

Let Force= F ------------(say)

Pressure$=\frac{Force}{Area}$

Force=Area x Pressure

$F=2\times {10}^5$ N

Work Done= Force x Displacement

Work Done$=(2\times {10}^5)\times 5\times {10}^{-3}={10}^{3}J.$