Question

The pressure difference across a pipe of length $5cm$ is $2\times {10}^{3}Pa$. Work done by the pressure in forcing $2m^3$ of water through the pipe in joule is :

• A. $4\times {10}^5$
• B. $2\times {10}^5$
• C. $2\times {10}^4$
• D. $4\times {10}^3$

Answer 1

The correct option is D $4\times {10}^3$

work done$=F.d$
=pressure difference $\times A\times L=$pressure diference $f\times Q$
$=2\times {10}^3\times 2$
$=4\times {10}^{3}J$