Question

The pressure exerted by 10 litres of gas at 272 K is 1.6 atm. What pressure would be exerted, in atm, by the gas at 409 K, provided that the volume remains constant?

Answer 1

This is dealt by using Gay Lussac's law, which states that volume remaining constant, the pressure exerted by a gas is directly proportional to its temperature.

i.e $P\alpha T$ or $\frac{P}{T}=k$ where $k$ is a constant.

Thus, $\frac{P_1}{T_1}=\frac{P_2}{T_2}$
According to the question, $P_1$= 1.6 atm, $T_1$= 272K, $T_2$= 409 K, $P_2$ = ?

Thus, $\frac{1.6}{272}=\frac{P_2}{409}$

Hence, $P_2$= 2.4 atm