The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V L volume is 1 atm. When the temperature is increased by 10∘C in the same vessel the pressure increases by 10%. The value of t is –
Apply Gay – lussac’s law; P1T1=P2T2
P1=1 atm P2=1+(10100×1)=110100=1.1 atmT1=(t+273)K T2=(t+283)K1(t+273)=1.1(t+283)
1.1t + 300.3 = t + 283
0.01t = 17.3
t=−173∘C
∴ t = 173 + 273 = 100 K