The pressure exerted by 12 g of an ideal gas at t- C in a vessel of V L volume is 1 atm- When the temperature is increased by 10- C in the same vessel the pressure increases by 10 - The value of t is -A- 173- CB- 173 kC- 100- CD- 100 k

The correct option is D Apply Gay – lussac’s law; P_1/T_1=P_2/T_2 P_1 = 1 atm P_2 = 1+ ( 10/100× 1 )=110/100=1.1 atm T_1 = (t+273)K T_2=(t+283)K 1/(t+2 ...

705

You visited us 705 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Bulk Modulus

The pressure ...

Question

The pressure exerted by 12g of an ideal gas at $t^{\circ} C$ in a vessel of V L volume is 1 atm. When the temperature is increased by $10^{\circ} C$ in the same vessel the pressure increases by $10 %$ . The value of t is –

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D

Apply Gay – lussac’s law; $\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

$P_{1} = 1 a t m P_{2} = 1 + (\frac{10}{100} \times 1) = \frac{110}{100} = 1.1 a t m T_{1} = (t + 273) K T_{2} = (t + 283) K \frac{1}{(t + 273)} = \frac{1.1}{(t + 283)}$

1.1t + 300.3 = t + 283

0.01t = 17.3

$t = - 173^{\circ} C$

$∴$ t = 173 + 273 = 100 K

Suggest Corrections

Similar questions

Q. The pressure exerted by

12 g

of an ideal gas at temperature

t^{\circ} C

in a vessel of

V

litre is one atmosphere. When the temperature is increased by

10^{\circ} C

at the same volume, the pressure increases by

10 %

. Calculate the temperature

t

and volume

V

(Molecular mass of the gas

= 120

Q. The pressure exerted by 12 g of an ideal gas at temperature

t^{o}

C in a vessel of volume

V

is one atm. When the temperature is increased by 10 degrees at the same volume, the pressure increases by 10%. Calculate the temperature

t

and volume

V

[Molecular weight of gas = 120]

The pressure exerted by 12 g of an ideal gas at temperature

t^{\circ} C

in a vessel of volume

V

litre is 1 atm. When the temperature is increased by

10^{\circ} C

at the same volume, the pressure increases by 10%. Calculate the volume of

V

[Molecular weight of the gas is 120. Write the value of V

\times

1000 Value]

Q. The pressure exerted by

12 g

of an ideal gas at temperature

1^{o} C

in a vessel of volume

V

litre is one atm. When the temperature is increased by

10

degrees at the same volume, the pressure increases by

10

%. Calculate the temperature

t

and volume

V

. (Molecular weight of the gas

= 120

)

Q. The pressure exerted by

12 gm

of an ideal gas at

t^{\circ} C

in a vessel of volume v litre is one atm. When the temperature is increased by

10^{\circ} C

at the same volume, the pressure increases by 10%. Calculate the temperature t (in K) (Mol. Wt. of gas = 120)

Join BYJU'S Learning Program

The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V L volume is 1 atm. When the temperature is increased by 10∘C in the same vessel the pressure increases by 10%. The value of t is –

The correct option is D Apply Gay – lussac’s law; P1T1=P2T2 P1=1 atm P2=1+(10100×1)=110100=1.1 atmT1=(t+273)K T2=(t+283)K1(t+273)=1.1(t+283) 1.1t + 300.3 = t + 283 0.01t = 17.3 t=−173∘C ∴ t = 173 + 273 = 100 K

The pressure exerted by 12g of an ideal gas at $t^{\circ} C$ in a vessel of V L volume is 1 atm. When the temperature is increased by $10^{\circ} C$ in the same vessel the pressure increases by $10 %$ . The value of t is –