You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mole Fraction

The pressure ...

Question

The pressure exerted by 6.0g of methane gas in a 0.03 m $^{3}$ vessel at 129 $^{o}$ C is (Atomic masses : C = 12.01 H = 1.01 and R = 8.314 J K $^{- 1}$ mol $^{- 1}$ ) :

215216 Pa

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13409 Pa

No worries! We‘ve got your back. Try BYJU‘S free classes today!

41648 Pa

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

31684 Pa

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 41648 Pa
Given, mass of $C H_{4}$ , $w = 6 g$
Volume of $C H_{4}$ , $V = 0.03 m^{3}$
T = 129 $^{o}$ C = 129 + 273 = 402 K
R = 8.314 J K $^{- 1}$ mol $^{- 1}$

Molecular mass of $C H_{4}$ , $M = 12.01 + 4 .04 = 16.05$

$P V = n R T = \frac{w}{M} R T$

$∴ P = \frac{w}{M} \frac{R T}{V} = \frac{6}{16.05} \times \frac{8.314 \times 402}{0.03}$

$= 41647.7 P a \approx 41648 P a$

Suggest Corrections

Similar questions

Q. The pressure exerted by

6.0 g

of methane gas in

a 0.03 m^{3}

vessel at

129^{\circ} C

is :

(Atomic masses :

C = 12.01, H = 1.01

and

R = 8.314 J K^{- 1} m o l^{- 1})

Q. The pressure exerted by

6.0 g

of methane gas in a

0.03 m^{3}

vessel at

129^{\circ} C

(

Atomic masses :

C = 12.01, H = 1.01

and

R = 8.314 {JK}^{- 1} {mol}^{- 1}

)

Q. The pressure exerted by a non- reactive gaseous mixture of

6.4 g

of methane and

8.8 g

of carbon dioxide in a

10 L

vessel at

27^{\circ}

C is ____

k P a

(Round off to the Nearest Integer).
[Assume gases are ideal,

R = 8.314 J m o l^{- 1} K^{- 1}

Atomic masses :

C = 12.0 u, H : 1.0 u, O : 16.0 u

]

Q. What will be the pressure exerted by a mixture of

3.2 g

of methane and

4.4 g

of carbon dioxide contained in a

9 {dm}^{3}

flask at

27^{\circ} C

?
(Given :

R = 8.314 {J K}^{- 1} {mol}^{- 1}

)

Q. What is the pressure of

H C l

gas at

- 40^{\circ} C

if its density is

8.0 k g m^{- 3}

(R = 8.314 J K^{- 1} m o l^{- 1})

Join BYJU'S Learning Program

The pressure exerted by 6.0g of methane gas in a 0.03 m3 vessel at 129o C is (Atomic masses : C = 12.01 H = 1.01 and R = 8.314 J K−1 mol−1) :

The correct option is C 41648 PaGiven, mass of CH4 , w=6gVolume of CH4 , V=0.03m3 T = 129oC = 129 + 273 = 402 K R = 8.314 J K−1 mol−1 Molecular mass of CH4 , M=12.01+4.04=16.05 PV=nRT=wMRT ∴P=wMRTV=616.05×8.314×4020.03 =41647.7Pa≈41648Pa

The pressure exerted by 6.0g of methane gas in a 0.03 m $^{3}$ vessel at 129 $^{o}$ C is (Atomic masses : C = 12.01 H = 1.01 and R = 8.314 J K $^{- 1}$ mol $^{- 1}$ ) :