Question

The pressure exerted by a force of $50N$, normal to the nail of area $1m{m}^2$ is

• A. $5\times {10}^7$ Pa
• B. $5\times {10}^6$ Pa
• C. $5\times {10}^5$ Pa
• D. $5\times {10}^4$ Pa

Answer 1

The correct option is A $5\times {10}^7$ Pa

Given:

Force $F=50N$

Area $A=1m{m}^2=\left({10}^{-3}m\right)\times \left({10}^{-3}m\right)={10}^{-6}{m}^2$

We know that,

Pressure $P=\frac{F}{A}=\frac{50}{{10}^{-6}}=5\times {10}^{7}N/m^2$

Also, $1N/m^2=1Pa$

So pressure $P=5\times {10}^{7}Pa$

Answer: $\left(A\right)$