Question

The pressure exerted by the weight of a cubical block of a side $3cm$ on the surface is $5Pa$. The force acting on the surface $p\times {10}^{-4}N$ then p=

Answer 1

Area = $3cm\times 3cm=9{cm}^2=9\times {10}^{-4}{m}^2$

& Pressure exterted = 5Pa

Since Pressure = $\frac{Force}{Area}$

Force = Pressure $\times$ Area

Force = $9\times {10}^{-4}\times 5N$

= $45\times {10}^{-4}N.$