Question

The pressure in the tyre of a car is four times the atmospheric pressure at 300 K. If this tyre suddenly bursts, its new temperature will be $(\gamma =1.4)$

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

For adiabatic process $\frac{T^{\gamma }}{P^{\gamma -1}}=constant$

$\Rightarrow \frac{T_2}{T_1}={\left(\frac{P_1}{P_2}\right)}^{\frac{1-\gamma }{\gamma }}\Rightarrow \frac{T_2}{300}=(\frac{4}{1}{)}^{\frac{(1-1.4)}{1.4}}\Rightarrow T_2=300(4{)}^{-\frac{0.4}{1.4}}$