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Question

The pressure inside two soap bubbles are 1.01 and 1.02 atmosphere respectively, then the ratio of their volume:

A
102:101
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B
(102)3:(101)3
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C
8:1
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D
2:1
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Solution

The correct option is C 8:1
Excess pressure in bubble A is
1.01 - 1 = 0.01 atmosphere
and Excess pressure in bubble B is
1.02 - 1 = 0.02 atmosphere
By excess pressure formula
ΔP=4TR
0.01=4TRA and
0.02=4TRB
So, RARB=21
Now, volume is proportional to (radius)3
VAVB=(RARB)3=(21)3=81

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