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Question

The pressure necessary to obtain 50% dissociation of PCl5 at 400 K is numerically equal to how many times the value of the equilibrium constant Kp

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Solution

PCl5will dissociate as,
PCl5PCl3+Cl2
t=0 1 0 0
t=teq 0.5 0.5 0.5
So, total moles at equilibrium = 0.5+0.5+0.5=1.5
Let the total pressure be P
Again,
Kp=PPCl3×PCl2PPCl5
Kp=0.51.5P×0.51.5P0.51.5P
Kp=P3
3Kp=P

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