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Question

The pressure of 1 g of an ideal gas A at 300 K is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at the same temperature, the pressure becomes 3 bar. Which of the following is correct?
(mA = mass of gas A; mB = mass of gas B)

A
mB=4 mA
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B
mA=3 mB
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C
mB=3 mA
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D
mA=mB
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Solution

The correct option is A mB=4 mA
Given,
Mass of gas A, wA=1 g
Mass of gas B, wB=2 g
pA=2 bar
Ptotal=3 bar
Ptotal=pA+pB
pB=32=1 bar
PV=nRTPV=WMRT
pAmAwA=pBmBwB or 2×mA1=1×mB2 or mAmB=14 or mB=4 mA

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