Question

The pressure of ${10}^3$ dyne/cm2 is equivalent to :

• A. $10N/m^2$
• B. ${10}^{2}N/m^2$
• C. ${10}^{-2}N/m^2$
• D. ${10}^{-1}N/m^2$

Answer 1

The correct option is B ${10}^{2}N/m^2$

Here the CGS unit of pressure is $dyne/c{m}^2$ and SI unit of it is $Newton/m^2$.

Pressure $=$ force/area

Now SI unit of force is $N$ and CGS unit of it dyne.

$1N=1kg\times 1m/s^2$ (according to $F=ma$ )

$=1000gm\times 100cm/s^2={10}^{5}dyne$

Thus, $1N/m^2=\frac{{10}^{5}dyne}{({10}^2{)}^{2}c{m}^2}=10dyne/c{m}^2$

Therefore, ${10}^{3}dyne/c{m}^2={10}^{2}N/m^2$