Question

The pressure of 20L of a gas kept at 300 K is found to be 2 atm. If the pressure is increased to 3 atm at the same temperature, what will be the new volume?

Answer 1

According to Boyles law,
PV = constant
Therefore, $P_1{V}_1=P_2{V}_2$

Here, $P_1=2\mathrm{atm}{V}_1=20L{P}_2=3\mathrm{atm}{V}_2=?$

$\therefore 2\times 20=3\times V_2$

$\mathrm{Thus},V_2=\frac{2\times 20}{3}=13.3L$