Question

The pressure of a $1:4$ mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?

• A. $0.8\times {10}^{4}atm$
• B. $0.008N{m}^{-2}$
• C. $8\times {10}^{4}N{m}^{-2}$
• D. $0.25atm$

Answer 1

Answer: (C)

$8\times {10}^{4}N{m}^{-2}$

$p_{O_2}=x_{O_2}\times P_{total}$
Given: $P_{total}=1atm,x_{O_2}=\frac{4}{5}$
$p_{O_2}=\frac{4}{5}\times 1=0.8atm$
$(\because 1atm=1.01325\times {10}^{5}Pa$ or $N{m}^{-2})$
$=0.8\times {10}^{5}N{m}^{-2}=8\times {10}^{4}N{m}^{-2}$.