Question

The pressure of a liquid is plotted on the Y-axis at a depth h in a liquid of density $\rho$ and the value of h on the X-axis , the graph is a straight line. The slope of the straight line is : (g $=$ acceleration due to gravity )

• A. $\rho g$
• B. $1/\rho g$
• C. $\rho /g$
• D. $g/\rho$

Answer 1

The correct option is A $\rho g$

Slope of straight line is $\frac{Pressure}{depth\left(h\right)}$.
We know that pressure at a depth of $h$ is $P$ = $\rho gh$,
where $P$ is pressure at a depth of $h$,
$\rho$ is the density of liquid.
$g$ is acceleration due to gravity.
$h$ is liquid column depth.
So, $\frac{P}{h}=\rho g$.
So, slope of the straight line is $\rho g$.