The Pressure of the gas in a constant volume gas thermometer is 80 cm of mercury in melting ice. When the bulb is placed in a liquid, the pressure become 160 cm of mercury. Find the temperature of the liquid.

946.30 K

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546.30 K

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446.30 K

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346.30 K

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Solution

The correct option is D 546.30 K
Since the volume of gas in thermometer is constant,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

Since temperature of melting ice is $273.15 K$ ,

$\frac{80}{273.15} = \frac{160}{T_{2}}$

$T_{2} = 2 (273.15) K = 546.30 K$

Answer is $546.30 K$

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