the pressure of water in a water pipe when tap is opened and closed is respectively 3 * 10^5 N/m^2 and 3.5 * 10^5 N/m^2. With open tap, the velocity of water flowing is

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Q. The pressure of water in a water pipe when tap is opened and closed is respectively

3 \times 10^{5} N / m^{2}

and

3.5 \times 10^{5} N / m^{2}

. With open tap, the velocity of water flowing is

Q. The pressure of water in a water pipe when tap is opened and closed in respectively

3 \times 10^{5} N / m^{2}

and

3.5 \times 10^{5} N / m^{2}

. Determine the velocity of flow when tap is open?

Q. A manometer connected to a closed tap reads

3.5 \times 10^{5} {N/m}^{2}

. When the valve is opened, the reading of the manometer falls to

3.0 \times 10^{5} {N/m}^{2}

, then the velocity of flow of water is:
(consider the water pipe to be horizontal)

A manometer connected to a closed tap reads 3.5 $\times$ $10^{5}$ N/ $m^{2}$ . When the valve is opened, the reading of manometer falls to 3.0 $\times$ $10^{5}$ N/ $m^{2}$ , then velocity of flow of water is

Q. A manometer connected to a closed tap reads

3.5 \times 10^{5} {N/m}^{2}

. When the valve is opened, the reading of the manometer falls to

3.0 \times 10^{5} {N/m}^{2}

. Then, the velocity of flow of water is:-

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