Question

The pressure of water on the ground floor is $40,000Pa$ and on the first floor is $10,000Pa$. The height of the first floor is $xm.$ Then $x=?$
(Take : density of water = $1000kg{m}^{-3}$, $g=10m{s}^{-2}$)

• A. $3$
• B. $4$
• C. $6$
• D. $8$

Answer 1

The correct option is A $3$

Pressure of water on the ground floor $=P_1=40000Pa$
Pressure of water on the first floor $=P_2=10000Pa$
Density, $\rho =1000kg/m^3$
We know that, $P_1-P_2=\rho gh$
$\Rightarrow 40000-10000=1000\times 10\times h$
$\therefore h=3m$