The pressure on a swimmer $20$ m below the surface of water at sea level is

1.0

atm

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2.0

atm

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2.5

atm

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3.0

atm

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Solution

The correct option is D $3.0$ atm
Given,
$P_{0} = 1 a t m = 1 \times 10^{5} P a$
$h = 20 m$
$ρ = 1000 k g / m^{3}$
$g = 10 m / s^{2}$
The pressure on a swimmer $20 m$ below the surface of water at sea level is
$P = P_{0} + ρ g h$
$P = 1 \times 10^{5} + 1000 \times 10 \times 20$
$P = 3 \times 10^{5}$
$P = 3 a t m$
The correct option is D.

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The pressure on a swimmer 20 m below the surface of water at sea level is

The correct option is D 3.0 atmGiven,P0=1atm=1×105Pah=20mρ=1000kg/m3g=10m/s2The pressure on a swimmer 20m below the surface of water at sea level isP=P0+ρghP=1×105+1000×10×20P=3×105P=3atmThe correct option is D.

The pressure on a swimmer $20$ m below the surface of water at sea level is