Question

The pressure P of a gas and its mean translational KE per unit volume are related as:

• A. $P=\frac{1}{2}E$
• B. $P=E$
• C. $P=\frac{3}{2}E$
• D. $P=\left(\frac{2}{3}\right)E$

Answer 1

The correct option is C $P=\frac{3}{2}E$

$\begin{array}{c}\therefore V_{rms}=\sqrt{\frac{3PV}{M}}\\ E=\frac{1}{2}M{V_{rms}}^2=\frac{3}{2}PV=\frac{3}{2}P\left[\therefore V=1\right]\end{array}$

Ans. (C)