The price of 1 kg oranges is thrice the price of 1 kg apples. Which of the following linear equation represents the given statement ?
(Assume the the price of 1 kg oranges to be x and of 1 kg apples to be y)
A
x - 3y = 0
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B
2x + 1 = y
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C
x + 3y = 0
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D
3x - y = 0
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Solution
The correct option is Ax - 3y = 0 Given, the price of 1 kg of oranges is x and that of 1 kg of apples is y.
According to the given condition, the price of the 1 kg oranges is three times the price of the 1 kg apple.
So, x = 3y.
Therefore, x - 3y = 0