Question

The price of $10$ chairs is equal to that of $4$ tables. The price of $15$ chairs and $2$ tables together is $Rs.4000$. Find the total price of $12$ chairs and 3 tables.

• A. $Rs.3500$
• B. $Rs.3750$
• C. $Rs.3840$
• D. $Rs.3900$

Answer 1

The correct option is D $Rs.3900$

Let the cost of a chair and cost of table be $Rs.x$ and $Rs.y$ respectively.

Then, $10x=4y$ or $y=\frac{5}{2}x$

According to the diven condition,

$\Rightarrow$ $15x+2y=4000$

$\Rightarrow$ $15x+2\times \frac{5}{2}x=4000$

$\Rightarrow$ $20x=4000$

$\therefore$ $x=200$.

So, $y=\frac{5}{2}\times 200=500$

Hence, the cost of $12$ chairs and $3$ tables $=12x+3y$

$\Rightarrow$ $Rs.(12\times 200+3\times 500)$

$\Rightarrow$ $Rs.(2400+1500)=Rs.3900$

$\therefore$ Cost of $12$ chairs and $3$ tables is $Rs.3900$.