The price of an article rises by $25 %$ every odd year and falls by $20 %$ next year. Which of the following statement is correct about the price exactly after $10$ years?

Price would have risen by

50 %

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The price would have fallen by

20 %

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The price would remain as it is

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The price would have risen by

25 %

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Solution

The correct option is C The price would remain as it is
$L e t t h e p r i c e o f t h e a r t i c l e b e x, a f t e r y e a r 1, p r i c e = x + \frac{25}{100} x = 1.25 x, a f t e r y e a r 2, p r i c e = 1.25 x - \frac{20}{100} \times 1.25 x = 1.00 x, A f t e r e a c h o d d y e a r, p r i c e = 1.25 x, a n d a f t e r e v e n y e a r s 1 x$

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The price of an article rises by 25% every odd year and falls by 20% next year. Which of the following statement is correct about the price exactly after 10 years?

The correct option is C The price would remain as it isLetthepriceofthearticlebex,afteryear1,price=x+25100x=1.25x,afteryear2,price=1.25x−20100×1.25x=1.00x,Aftereachoddyear,price=1.25x,andafterevenyears1x

The price of an article rises by $25 %$ every odd year and falls by $20 %$ next year. Which of the following statement is correct about the price exactly after $10$ years?