The primary coil of a transformer has 800 turns and the secondary coil has 8 turns.It is connected to a 220 V a.c. supply.What will be the output voltage?

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Solution

$\frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}} \Rightarrow \frac{E_{s}}{220} = \frac{8}{800} \Rightarrow E_{s} = 2.2 V$

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The primary coil of a transformer has 800 turns and the secondary coil has 8 turns.It is connected to a 220 V a.c. supply.What will be the output voltage?

EsEp=NsNp⇒Es220=8800⇒Es=2.2 V

$\frac{E_{s}}{E_{p}} = \frac{N_{s}}{N_{p}} \Rightarrow \frac{E_{s}}{220} = \frac{8}{800} \Rightarrow E_{s} = 2.2 V$