The primary coil of a transformer is connected to a $60 V$ ac source. The secondary coil is connected to a $330$ load. The turns ratio is 3:1. What is the secondary voltage?

2 V

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20 V

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180 V

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18 V

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Solution

The correct option is A $20 V$
Turns ratio, $n = \frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$ where p for primary coil and s for secondary coil.
Given, $V_{p} = 60 V$ and $n = 3$
So, $V_{s} = V_{p} / n = 60 / 3 = 20 V$

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The primary coil of a transformer is connected to a 60V ac source. The secondary coil is connected to a 330 load. The turns ratio is 3:1. What is the secondary voltage?

The correct option is A 20VTurns ratio, n=NpNs=VpVs where p for primary coil and s for secondary coil. Given, Vp=60V and n=3So, Vs=Vp/n=60/3=20V

The primary coil of a transformer is connected to a $60 V$ ac source. The secondary coil is connected to a $330$ load. The turns ratio is 3:1. What is the secondary voltage?

The correct option is A $20 V$
Turns ratio, $n = \frac{N_{p}}{N_{s}} = \frac{V_{p}}{V_{s}}$ where p for primary coil and s for secondary coil.
Given, $V_{p} = 60 V$ and $n = 3$
So, $V_{s} = V_{p} / n = 60 / 3 = 20 V$