The primary of a transformer has $400$ turns while the secondary has $2000$ turns. If the power output from the secondary at $1000 V$ is $12 k W$ , what is the primary voltage?

200 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

400 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

500 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $200 V$
$N_{P} = 400, N_{S} = 2000$ and $V_{S} = 1000 V$
$\frac{V_{P}}{V_{S}} = \frac{N_{P}}{N_{S}}$
$V_{P} = \frac{V_{P} \times N_{P}}{N_{S}} = \frac{100 \times 400}{2000} = 200 V$

Suggest Corrections

Similar questions

Q. A power transformer has

50

turns for primary and

300

turns for secondary. What is turns ratio? How much is secondary voltage with primary voltage of

230

V

Q. The primary of a transformer has

100

turns and operates at

100 V

. The number of turns in the secondary, if the output voltage is

2000 V

is _________.

Q. An ideal transformer has 400 turns in the primary and 200 turns in the secondary. If the primary is connected to a 12 V battery, then the secondary voltage is

A transformer has $1500$ turns in the primary coil and $1125$ turns in the secondary coil. If the voltage in the primary coil is $200 V$ , then the voltage in the secondary coil is

Q. A

3 - ϕ, Y - Δ

transformer has secondary to primary turns ratio per phase of 5. If the primary side voltage of transformer is 400 V, then value of secondary voltage will be

Join BYJU'S Learning Program

The primary of a transformer has 400 turns while the secondary has 2000 turns. If the power output from the secondary at 1000V is 12kW, what is the primary voltage?

The correct option is A 200VNP=400,NS=2000 and VS=1000VVPVS=NPNSVP=VP×NPNS=100×4002000=200 V

The primary of a transformer has $400$ turns while the secondary has $2000$ turns. If the power output from the secondary at $1000 V$ is $12 k W$ , what is the primary voltage?

The correct option is A $200 V$
$N_{P} = 400, N_{S} = 2000$ and $V_{S} = 1000 V$
$\frac{V_{P}}{V_{S}} = \frac{N_{P}}{N_{S}}$
$V_{P} = \frac{V_{P} \times N_{P}}{N_{S}} = \frac{100 \times 400}{2000} = 200 V$