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Byju's Answer
Standard XII
Mathematics
Algebra of Complex Numbers
The principal...
Question
The principal mod-amp form of
2
−
√
3
+
i
is
A
(
√
6
−
√
2
)
c
i
s
5
π
12
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B
2
√
3
c
i
s
π
12
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C
3
√
2
c
i
s
5
π
12
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D
2
√
2
c
i
s
5
π
12
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Solution
The correct option is
A
(
√
6
−
√
2
)
c
i
s
5
π
12
θ
=
t
a
n
−
1
(
b
a
)
=
t
a
n
−
1
(
1
2
−
√
3
)
=
5
π
12
Modulus
=
√
(
2
−
√
3
)
2
+
1
=
√
4
+
3
−
4
√
3
+
1
=
√
8
−
4
√
3
=
2
√
2
−
√
3
=
(
√
6
−
√
2
)
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0
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