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Question

The principal solution(s) for cosx=12 is/are
  1. 3π4
  2. 5π4
  3. 11π4
  4. 13π4


Solution

The correct options are
A 3π4
B 5π4
cosx=12
cosx=cos(ππ4)
cosx=cos(3π4)
x=2nπ±3π4,nZ    ...(1)

We know that, for principal solutions, θ[0,2π]
Now, put n=0 in (1), we get x=3π4
Similarly, put n=1, we get x=2π3π4=5π4
Principal solutions are 3π4,5π4.

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